@zero-profit report and giveaway

in #lottery5 years ago

I am a fair upvote bot that is paying 100% of all gains to its delegators. I work very flexible saving upvotes when you dont post and automtaically switch to steem payouts when needed. Furhtermore you can always use your voting power to vote by sending me a memo with a post to upvote. For more information please read my introduction

This week I generated a revenue of 0.422 STEEM from a delegation of 100 STEEM for an account that never posts. When posting regularly you can expect roughly 10 percent more. The excat numbers fluctuate due to curation rewards and conversion markets.

Delegation Links: 20sp, 50 sp, 100 sp, 200 sp, 500 sp.

To advertise myself I am giving away free lifetime upvote-shares in a lottery. Simply upvote this post to participate. According to my philosophy the payout of this post is shared with all delegators.


This post is promoted by @reversed-bidbot as a lottery with a jackpot of 0.202 steem!

Tickets are distributed according to the value of your upvotes with a multiplier of 5000.0.
Upvote the post to participate and claim your tickets!

The jackpot is paid in upvote_shares by @zero-profit, giving you lifetime upvotes and weekly curation payouts. Find more information here.

Follow me to also earn steem on my other promoted posts; or use @reversed-bidbot to hold your own raffles. For more details please visit my discord server or read my introduction post

I was called to perform a provably fair random drawing for @reversed-bidbot!

There are a 1028 tickets participating in this round.
@inversionistam holds tickets number 0 - 30
@smjn holds tickets number 31 - 800
@frdem3dot0 holds tickets number 801 - 862
@felipejoys holds tickets number 863 - 1027
The merkle root of the block in which this post will appear determines the winner.

The block in which the above post is included has a merkle root of b2094f3137c4d281c697b23c260f504ae1a10892.
To find the winner we:

  1. Convert the merkle root into base 10:
    b2094f3137c4d281c697b23c260f504ae1a10892 = 1016407962531984298647597576555870007493849581714.
  2. Compute the residual after dividing by the number of tickets: 1016407962531984298647597576555870007493849581714 mod 1028 = 1026.
  3. This is the winning ticket, held by @felipejoys.


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