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So you can write B as B=invXDX where X is the eigen matrix with corresponding eigenvalues on the diagonal of the diagonal matrix D. It is then easy compute B^m you then need to find an m such that B^m mod size of your matrix is equal to the identity matrix. So this gives you equations to find the periodicity

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Again to find m I will have to iterate till I see identity matrix right? So that means it is sometimes computationally intensive right?

When you iterate you only have to compute D^m D is a diagonal matrix so that is pretty easy to compute. X and invX stay the same. More specifically B^m=invX D^m X

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