Reduction Formula for the Integral of ∫tan^n(x)dx
So far, we have worked through the steps to derive the reduction formulas (formulae) for the integrals of powers of sine and cosine. Let's now have a look at how we derive the reduction formula for integrating powers of the tangent function.
![i1.png](https://steemitimages.com/DQmNqQ8qsX3W28PxAdsuNJ6Gs8xk8DCnBbREzZNNcKrTg1R/i1.png)
As it turns out, and counter intuitively, deriving this reduction formula is easier than for sine and cosine. The first step is the same - break up the integrand into a multiple of lower powers.
Let's reserve a tan-squared term and rewrite the integral as...
![i2.png](https://steemitimages.com/640x0/https://steemitimages.com/DQmeENgEDrLBdxdBY59xdPddemTrTr69u6RxitC4Cc7SWst/i2.png)
Now, with the Pythagorean Identity, the tan-squared term can be rewritten as...
![i3.png](https://steemitimages.com/DQmT9JBctYtP1AUeGtWHDzfXz1gAKE74oQEQgMe4daC7DUx/i3.png)
...and thus, the integral becomes...
![i4.png](https://steemitimages.com/640x0/https://steemitimages.com/DQmVGeCva2S5kGuruKBnDz7DR4kDZJ1NJaD2zXtXMpBFcdW/i4.png)
Now, for the first integral on the right-hand side, we can use a simple u-substitution if we let...
![i5.png](https://steemitimages.com/DQmUhFdYW8YkXgBjWXC4kDtHY2ReYimiqNLBeLUxE5x2K5f/i5.png)
And thus, the first integral on the right-hand side becomes...
![i6.png](https://steemitimages.com/640x0/https://steemitimages.com/DQmX2XRJM3MboWbesq4B4K244b9c1pie9FX57emuiZKh878/i6.png)
And thus far, we have...
![i7.png](https://steemitimages.com/DQmVKij1ffXs1tLac2YbHMPRLXHKQrmxYnKDyUfnq78CshZ/i7.png)
To complete, all we need to do is back substitute tan(x) for u into the above expression.
![i8.png](https://steemitimages.com/640x0/https://steemitimages.com/DQmUJhaGXxe7eGs9krjaULBnuaZP85uv9nhivzWkbRy692A/i8.png)
And there you have it - we've derived the reduction formula for the integral of powers of tan(x).
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