The Steemit Crypto Challenge #9

in #steemitcryptochallenge8 years ago (edited)

Prepare - Uncover - Outwit - Find - WIN!



Welcome to the Steemit Crypto Challenge. You may know this series of puzzles or not. Let me give you a quick introduction. You are looking to find a solution. Anything can be a hint. You will start with two hints given and need to seek the right path. So you think you are good with riddles? Are you a big master of crypto puzzles? Find the answer. Sometimes the hints are hidden, not visible to the eye. But they are here.

Can you follow your intuition and stay on the right track? The first to reveal a hint will win a prize. The first to attain understanding with the right answer will receive their bigger reward.


Here is your first hint


Here is your second hint


Rules, Terms and Conditions

You will need to employ all of your skills to solve this crypto-puzzle. This isn't for the weak-hearted.
Don't limit your creativity, look forward and look behind the curtain!
Take advantage of:

  • Image (and reverse) searches
  • Steemit
  • Wikis or Encyclopedias
  • Filesharing Sites
  • Sound, video, and image recording manipulation
  • You will receive hints from time to time.

    Stay frosty and don't get burned in that inferno


    Don't be limited to the list above, get creative! Think you got in the bag? How hard could it be? Surely, your Code Solvers and Image Manipulation Translators are up to date, piece of cake! All submissions are due by Saturday October, 29th @ 6pm (UTC -4) The First Prize reward is 100 Steem. Additional: 10SBD per new hint uncovered. (This challenge is not impossible, but you'll feel like it is). Special thanks goes to @blocktrades who sponsors this challenge.

    P.s.: Only two weeks left until the SteemFest! Hope to see you there!
    Another episode of Myth of Fact follows tomorrow.

    Happy hunting,
    Tim Said

    Cover image source

    UPDATE 1


    There is a certain pattern in the first puzzle. Think diagonally

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    la respuesta es 9
    Excelente post felicidades gracias por compartir

    No, it's e to the i times pi power!

    No :) try to find the right path

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