The shortest known unsolved propositionsteemCreated with Sketch.

in #math7 years ago (edited)

It was about 150 years ago that formal logic fused into mathematics. The language univerally used today is that of predicate logic in a form similar to the one introduced by Gottlob Frege. It can savely be said that without his monumental work, die Begriffsschrift, we wouldn't have computers already. This is because Alan Turings work on computation is an answer to David Hilberts Entscheidungsproblem, which relies on Freges logic. But this is the topic of an entirely different post.

Today we have a whole array of proper formalizations of concepts that have been worked with for hundrets of years. A major such theory is Peano Arithmetic, named after Giuseppe Peano and based on the Peano axioms.

The base of the language forms a symbol usually denoted by "0" and another one denoted by "S". The intended interpretation is that 0 denotes a natural number and Sn the "successor" of n, whenever n is a natural number. So for example, this implies that S0 is a number, and so is SS0. You may think of all those expressions as the number that's given by the amount of S's in it. Thus SSSSS0 represents the number 5. Later we introduce a binary operation "+" recursively. Then Sn may be written in a more elaborate way, as n+1. The same spiel goes for multiplication. One of the rules is then, for example

a + Sa = S(a+b)



This enables us to formalize and then prove, for example

3+4 = (3+3)+1


(image source)

The computer scientist Bauer had a program running in recent year, which studied short expressions in that language, and many others. The shortest one that's not solved for being true or false is the following.

∀a. ∃b. ∀x. ∀y. (a+b)·(a+b) != SS((SSx)·(SSy))

Here a,b,x and y denote any number and ∀ and ∃ should be read "for all" and "there exists".


Thus, roughly,

there are infinite numbers b, so that b squared minus 2 isn't for the form x·y

In other words, there are infinite primes p of the form p=b^2-2.

This makes the above claim the shortest unresolved problem.

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I had been editing the post - it's now in the text. SSn comes down to n+2.

Are you sure that this is really what you mean?
In other words, there are infinite primes p of the form p=b^2-2

Cause I think I just proved that...

The theorem that "I mean" is

∀a. ∃b. ∀x. ∀y. (a+b)·(a+b) != SS((SSx)·(SSy))

In words:

For any number a, there is a number b, so that for all pairs of numbers, call them x and y, the number a+b squared isn't twice the successor of the product of twice the successor of x and trice the successor of y.

If you define B=a+b, X=x+2 and Y=y+2, the thing reads

B^2-2 != X·Y

I.e. B^2-2 can't be factorized into any X and Y.

And I'm pretty sure that what it comes down to, yes :)

Ok cool thanks for the clarification!
I think my proof was wrong now after looking at it more...

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Hi, would like to include this in the next Math-Trail Magazine. Hope that's OK with you!

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