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RE: Interpretation of Circuit Diagram/Circuit Building

in Electronics Academy3 months ago (edited)
Hi @manuelhooks, It's good to see you and your activities in week 3. I have accessed your assignment task and come up with the below analysis.
  • You have a good and interesting information in your intro but avoid making it too long like this especially when handling task in the "Electronic Academy". It almost lost interest.

  • You have successfully handled your task 1 in a neat and simple format. And you have highlighted the key differences between the two circuits with some great observations.
    Hope other students can learn from that. However, I need to point out one thing - it's true LED is a type of diode, but it's good to be specific and clear. If it's "LED"- put it "light emitting diode ", don't just write diode. Even if you put it as "LED" that's even much better. This is in regards to your components listing on workshop 1.

  • Your task 2 was also done successfully with some clear interpretations and easy to understand steps to build the circuit.
    **Quick question: why was the LED light dull?

  • You have also explained the activities of the both circuits in task 3. That was a smart observation. However, highlighting all the conponents in that circuit could be an added advantage.

  • You have drawn a circuit of your choice in task 4 successfully.

  • Your task 5 is also an excellent job.


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  • Your approach to all the tasks were excellent and great effort indicating real interest in the class. And yes, electronic circuits are best enjoyed when they are built in real life. We hope to see your progress and activities in our up coming classes

  • Note that one of the instructions was for you to post the link of your assignment on the main lesson post!

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Thank you for the encouraging remarks.
All correction taken and effected.

Quick question: why was the LED light dull?

Fig 2 was powered by a 9v battery, the ressistance in the circuit was 1kΩ and the LED was bright. In task 2, the LED still had a 9v supply but its resistance was 2 resistors in series. (1kΩ + 1kΩ = 2kΩ)

Now that the resistance in the circuit is higher, power to the LED reduced and the LED become dull.

Buena respuesta, ahora la corriente encuentra mayor oposición y eso es lo que vemos reflejado en lo tenue de la luz led.

1_20210401_152726_0000.png

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