Logic Tests Series (2) - DECR 逻辑测试系列之二 - DECR

in #cn7 years ago (edited)

@justyy 's series of Logits Tests:

What you can do with this tiny programming language with only 4 instructions? Today, we are going to implement the DECR function which decrements the variable by one, for example, DECR(X) where X=5 will make X=4.

DECR(X) {

}

The only 4 instructions are: INCR, LOOP, ZERO and ASGN. And all variables hold non-negative integers. To make X decremented by 1, we can increment a temp variable by (X-1) times..

DECR(X) {
   ZERO(V1)
   LOOP(X) {
     ASGN(X, V1)
     INCR(V1)
  }
}

We translate this to C++, which might be a bit easy to understand.

void decr(unsigned int &x) {
   int v1 = 0;
   int xx = x;
   for (; x > 0; -- x) {
      xx = v1;
      v1 ++;
   }
   x = xx;
}

If you change the value of the loop variable x, the loop iteration count may be altered. Therefore, we declare a temp variable xx and assign the xx to X after loop when it gets incremented (x-1) times.


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@justyy 的逻辑测试系列:

这种只有4条语句的语言能做什么呢?今天我们来定义一个DECR函数,该函数就是把 变量 X 减一。

DECR(X) {

}

要求填写函数体,使用 INCR、LOOP、ZERO、和 ASGN 仅有的4个语句。我们不妨想一下,已知变量 X 是非负整数,那么我们只需要 循环 X-1次,每次把X从0加1即可。

DECR(X) {
   ZERO(V1)
   LOOP(X) {
     ASGN(X, V1)
     INCR(V1)
  }
}

我们翻译成 C++, 可能比较好懂一些:

void decr(unsigned int &x) {
   int v1 = 0;
   int xx = x;
   for (; x > 0; -- x) {
      xx = v1;
      v1 ++;
   }
   x = xx;
}

由于C++的 for 里改变 x 值会改变循环次数,所以我们用了一个临时变量 xx。

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// Later, it may be reposted to my blogs: justyy.com, helloacm.com and codingforspeed.com 稍后同步到我的中文博客和英文计算机博客

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原文首发于 https://Steemit.com 首发。感谢阅读,如有可能,欢迎Follow, Upvote, Reply, ReSteem (repost) @justyy 激励我创作更多更好的内容。

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Thanks for the information. I'm eager to learn from this programming.

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