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RE: Understanding Dynamical Systems: Introduction to Chaos Theory and Its Real Life Applications

in #steemstem6 years ago (edited)

I don't think it is.
The differential equation model of the swinging pendulum corresponds to a two-dimensional map. We assume that the pendulum is free, such that it can swing through 360° (frictionless pendulum). However, the motion of the pendulum is constrained to a circle whose radius corresponds to the length l, of the pendulum rod, while the angle of the pendulum is θ which is measured in radians.


Newton's law of motion F=ma can then be used to find the pendulum equation.
The differential equation governing the pendulum becomes:

mlӪ = F = -mgsinӨ. (This is according to Newton’s law of motion).

Therefore, the pendulum requires a two-dimensional state space.
For a solution to this differential equation (second order), two initial conditions must be defined i.e θ (0) and θ ̇(0) (first derivative). If just one is specified, then we cannot predict the future state of the pendulum.
However, if θ and θ ̇(first derivative) are specified at time t=0. We can uniquely determine θ (t) at the next instant.
You can check out:

CHAOS: Introduction to Dynamical systems. Kathleen T. Alligood, Tim D. Sauer
James A. Yorke. Springer: ISBN 0-387-94677-2
A book I read some years back during my Master’s degree.

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I said : F=ma does not directly specify a deterministic dynamical system since it is a second order ODE.

Observe that

mlӪ = F = -mgsinӨ. (This is according to Newton’s law of motion).

is a second order ODE. Observe that Ө' is not a dependent variable of this ODE. So you need to define it as a dependent variable then you can write the system as two first order ODEs and apply the uniqueness theorem of first order ODEs which induces flow.

I am trying to point out that if you have the equation

mlӪ = F = -mgsinӨ.

Then this does not induce a unique dynamical system since for example i could consider the system corresponding to the dependent variables defined by x=Ө , y=Ө' but also v=Ө , w=2Ө'

Is this clear?

F=ma does not directly specify a deterministic dynamical system since...

Your explanation is clear, but I just want you to get my point. This example is simplified with assumptions to make it fit the context in which I used it above. Those two initial conditions must be specified. There are still other systems which corresponds to a two dimensional state space and two initial conditions need to be specified for determinism and the law of motion is still F=ma


In fact, in the case of nonlinear methods,if the methods are used only when determinism is strong then there would be a limitation, but it is used even when determinism is weak.

interesting intellectual argument going on here, I will just observe.

Thanks for observing, its quite interesting and love this discussion and it revealing...thanks to @mathowl

Its really intellectual. I can say that they are digging deep for understanding.

Yeah I understand it is a simplifiction.

What do you mean with

in the case of nonlinear methods,if the methods are used only when determinism is strong then there is would be a limitation, but is used even when determinism is weak.

More specifically, what is strong determinism and what is weak determinism?

In using nonlinear methods (algorithms) on real (Field) data, there might be the absent of clear behavior as predicted by theoretical requirement that the data be deterministic to a very good approximation ( which has been reported in some research work I have seen). However, some qualitative information can still be obtained using these tools with some adjustments. This is what I mean by weak determinism.
(Sorry for my late response, I have been out of town)

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