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RE: #Chemistry Challenge 5
But as you said, the gasoline is a liquid, and the concentration of a liquid is constant, so ∆c would be zero, so you expect v to be zero in my answer?
But as you said, the gasoline is a liquid, and the concentration of a liquid is constant, so ∆c would be zero, so you expect v to be zero in my answer?
Let's calculate the concentration c of isooctane at t = 0 (using the volume at t = 0), and then consider how fast n(isooctane) decreases. Even if the liquid is transformed into gas you can calculate as if the volume would stay constant (the transformation from liquid into gas doesn't influence the decrease rate of isooctane).