Modelling Exponential Growth of Bacteria with dy/dx = ky

in #steemiteducation7 years ago (edited)

With the differential equation dy/dx = ky, we found the general solution to be y(x) = Aekx. We worked this out in my last post.

This equation lends itself to the modelling of exponential growth. Now in nature, nothing grows exponentially indefinitely - that would be quite unsustainable. But when observing phenomena under certain environments and reasonable time frames, this family of solutions can be a good approximation.

Here are 2 graphs to depict how this family of solutions behaves.

In graph 1, we keep the growth rate k = 1, thus y(x) = Aex, showing how the solution behaves for varying values of A...

graph_20170918_013021.png
Drawn with GraphSketch.com

In graph 2, we keep the coefficient A = 1, thus y(x) = ekx, showing how the solution behaves for varying values of k...

graph_20170918_013415.png
Drawn with GraphSketch.com

As you can see, k has a greater influence on the behaviour of the solution than A. And this make sense, because A is the quantity we begin with, but k is how fast or slow we grow.

Now, we tackle the bacterial growth problem:

Bacteria grow by division of cells, so the growth of a colony is proportional to the number present. In a deep wound, there are initially 20 anaerobic clostridium bacteria present. After 2 hours, the number has grown to 90. Use a differential equation to determine the number present after time t. When the number reaches 1000, the patient begins to develop symptoms of nerve poisoning from the toxins produced by the bacteria. How long does this take?

We develop the problem by noting that since the growth is proportional to the number present, the growth rate...

Eq1.png

Solving this differential equation we get the general solution...

Eq2.png

We can now find the explicit solution by applying the conditions given. Initially, we have 20 bacteria present, so...

Eq3.png

After 2 hours, we know the number has grown to 90, so...

Eq4.png

Solving for k, we get k = 0.75. And thus the explicit solution is:

Eq5.png

Finally, to find the time required to get to 1000, we just need to solve for t in the same fashion as above...

Eq6.png

We find t = 5.2 hours, or 5 hours and 12 minutes. Better get that wound cleaned quick!

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YESSSSS @masterwu! I am so happy to find this on steemit. I took a biological modeling course last semester, and this was our first homework assignment. A few weeks in, the class moved towards using the Gillespie Method for modeling protein expression. Definitely looking forward to more posts like this :D

Thank you @jshmu for the kind words. I love how mathematics applies in nature, so if I do find some more examples, I'll definitely post about them. :)

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