Integral of ∫cot^2(x)dx

In this video, we find the integral or anti-derivative of cot²(x). We approach this by first revising the derivative of cot(x), which equals -csc²(x).

Then, by the Pythagorean Trigonometric identity: cot²(x) + 1 = csc²(x). We can rearrange this equation to:

cot²(x) = csc²(x) - 1

Realising that -csc²(x) derivative of cot(x), we can write the above as:

cot²(x) = -d/dx[cot(x)] - 1

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