SEC-S20W4: Decision Making in programming; If-Then-Else
Hello friends and I warmly welcome you all to the SEC S20/W4 It is really interesting to have to share my thoughts in this challenge. I do hope we enjoy my article.
I found an optimal solution to this specific number such as 100 or 1307, starting from 1 and by using only about two operations. Multiplying by 2 or adding one. I would implore the backward strategy from the target 1. It will help to us minimum steps to approach target numbers in a universal way.
Backward Approach: This shows how we can reduce the target number back to 1 using the reverse method. These are 2 rules in this respect. If the target is an even number, the inverse of multiplication by 2 is division by 2, this is because previous numbers can be obtained by multiplying by 2, thus the inverse would be gotten by multiplying by 2. If target number is odd number, the inverse of adding 1 is performed by subtracting 1 from number. This ensures that most few operation be used, thus we will be able to grow faster by multiplication by 2 and addition of 1 where needed
Divide 100 by 2 100 ÷ 2= 50
50 is even so divided by 2 50 ÷ 2= 25
25 is odd so subtract 1 25 - 1= 24
24 is even so divided by 2 24÷2= 12
12 is even so divided by 2 12÷2= 6
6 is even so divided by 2 6÷2= 3
3 is odd so subtract 1 3-1= 2
2 is even so divided by 2 2÷2= 1
Reverse Operation:
Multiply 1 by 2 = 2
Add 1 = 3
Multiply by 2= 6
Multiply by 2= 12
Multiply by 2= 24
Add 1= 25
Multiply by 2= 50
Multiply by 2= 100
Operation 13709:
Start with 13709 it is odd so subtract 1.
13709-1 =13708
13708 is even so divided by 2 13708÷2= 6854
6854 is even so divided by 2 6864÷2= 3427
3427 is odd so subtract 1 3427-1= 3426
3426 is even so divided by 2 3426÷2= 1713
1713 is odd so subtract 1 1713-1= 1712
1712 is even so divided by 2 1712÷2= 856
856 is even so divide by 2 856÷2= 428
428 is even so divide by 2 428÷2= 214
214 is even so divided by 2 214÷ 2= 107
107 is odd so subtract 1 107-1= 106
106 is even so divided by 2 106÷2= 53
53 is odd so subtract 1 53-1= 52
52 is even so divided by 2 52÷2= 26
26 is even so divided by 2 26÷2= 13
13 is odd number so subtract 1 13-1= 12
12 is even so divided by 2 12÷2= 6
6 is even so divided by 2 6÷2=3
3 is odd so subtract 1 3-1=2
2 is even so divided 2 2÷2=1
Reverse Operation to reach 13709 from 1.
Start with 1
Multiply by 2= 2
Add 1= 3
Multiply by 2= 6
Multiply by 2= 12
Add 1= 13
Multiply by 2= 26
Multiply by 2= 52
Add 1= 53
Multiply by 2= 106
Add 1= 107
Multiply by 2= 214
Multiply by 2= 428
Multiply by 2= 856
Multiply by 2= 1712
Add 1= 1713
Multiply by 2= 3426
Add 1= 3427
Multiply by 2= 6854
Multiply by 2= 13708
Add 1= 13709
I have performed task while using the reverse method in varying steps. I reached from 1 to 13907 in about 20 steps. This is the generally accepted method to reach target numbers.
Boolean Variables are important for identifying true or false values. These values are represented by 0 for false and 1 for true. They help manage decisions and flow of program. Thy are used in conditional structures, loops and logical operations.
Purpose of Boolean Variables
Loop Control: These variables can be used to control loop such as for or while. It continues to run as long as conditions is false and it stops when condition becomes true as shown below
bool done= false; while (!done){ // some operations... done= true; // loop exists when 'done' becomes true }
Conditional Logic: These are variables are essential in conditional statement as if, else, switch. They help determine whether a particular code should be executed or not.
bool is Raining= true; If ( is Raining) { cout << "Take an umbrella!"<< end l; }
The variables Raining
is Boolean was initially true and checks conditions of rain then execute related code.
Explain Complicated Logic; These variables help to simply complicated logical problems by breaking them in bits into smaller parts. It improves readability and maintenance of code.
Why are they called that
The reason behind the Boolean traces down into the name George Boole The great English mathematician, he brought the Boolean algebra into play in the 19th century. He is known as the father of Boolean logic. The Boolean deals with binary values (0, 1) or (true, false). Everything encoded in the computer are in binary numbers of 0 and 1. Before understanding and interpreting. They are vital in running programs and proper decision making.
Conditional Operators are used in some condition, it provides a simple and express way to makinh decisions based on conditions. They are beneficial where if-else
statement come to play. They allow to choose between two values or results all a function of the condition.
Syntax Condition:
value_if_true:
value_if_false
It is written with a question mark? Guiding it, the true condition written after a colon is used and after that colon another condition
scenario;
int a= 10 b= 20; Int max = (a>b)? a:b; // if 'a' is greater than 'b' max is assigned 'a' otherwise 'b' cout <<Maximum value: "<<max <<end l;
int max= (a>b)
is condition if true
value will be a
if condition is false
value would be returned as an answer.
Ternary Operator:
It is the most common type of conditional operator, used to check conditions while returning one value from two as a result of condition whether true or false it involves three operand conditions, values if condition is true, values if condition is false.
AND Operators:
This operators allow to check two conditions at once. It turns true when both conditions are true and false if any on the condition differs.
A | B | A&&B |
---|---|---|
0 | 0 | false |
0 | 1 | false |
1 | 0 | false |
1 | 1 | true |
If two values are true
then if will return true
example of (a>b) && (c<d){ return true ; } {else return false;}
Logical Operators:
They are used to create complex conditions by combining simple ones. They used alongside conditional statement specifically if statement is used to check more than one condition at once.
OR Operators:
This allows us to check two conditions at once and returns, true
when one condition is true otherwise in other condition remains false
A | B | A or B |
---|---|---|
0 | 0 | false |
0 | 1 | true |
1 | 0 | true |
1 | 1 | true |
NOT Operators:
This operators allows to reverse values of boola expression, turns true
into false
and false
into true
The truth table of NOT Operator is these.
A | !A |
---|---|
True | False |
False | True |
I have about 5134 posts and 393sp, 68 followers and 95 following, it compared all values if showed all the values and answer too
I would run the program as before on the C++ I would get the input from users, after that calculate the sum and product of numbers, then check the sum and product. If sum of numbers is greater then my program would return to sum. If otherwise product is greater then it will return to product of numbers if it's greater than sum. From the program they are both equal.
This illustration shows that even house numbers are separated in one side, different from odd house numbers. Invariably if two eve house numbers are inputed on same side automatically they would be on one side, and same occurs in the odd house number. Importantly if two random numbers are picked both odd and even they would fall on opposite sides.
Using conditional statement parameter %
modulus operator, we use it to check whether odd or even, this if it gives a remainder then it's even, asides that it is odd. h1, h2 were variables used which stands for the houses respectively. It checks which house number belongs to each category. The message is relayed in the coed information above.
We are on the quest in search for a number which has more than 4 digits, divisible by 7 and not divisible by 3.
I initialized a number as integers, program back testing the condition in the question, checking a number with four digits would be 9999, checking of it is divisible by 7 and it falls in line. Checking if it is divisible by 3. Therefore tells us all that the number meets all conditions, in other cases it may not meet all conditions.
I chose three integers, first digit and second digit, it must accept two digits and then Ill separate both digits of numbers using quotient/ remainder applying condition on a digital of number. Condition taking both numbers and checking whether first digit is greater than second digit.
Program seeks for 2 digits number, first digit number are entered and is gotten by dividing by 10 thus the first digit is the quotient. Second digit is the remainder when the digit is divided by the 10 with modulus operator, program checks whether first number is great or equal to second. If integers are entered then both numbers are equal.
Cc;
@sergeyk
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