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RE: More n^2

in #non-linear7 years ago

We would in a different kind of hell:)
The flag war between @berniesanders and @haejin would be of epic proportions with all their bots.

Hmm, as a whale.. currently, with 10 bots, they cannot get more by delegating.
But with n^2, wouldn't delegating their SP to 10 bots would x100 their power.. delegating to 100 bots.. 10000x times the power.
Or are my calculations wrong?

But for the minnows it would indeed be a big incentive to use more social skills...
We would see way more vlogs and already successfull facebook users, I guess.

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Yes those calculations are wrong.

Can you point me to the right formula?
Your last article:
https://steemit.com/non-linear/@felixxx/why-n-2

If you were to use your vote on a post with already a bunch of r_shares, then upvoting that post would allow you to allocate much more rewards than if another account with 2x as much Steem Power voted on a different post with no other votes to stack on to.

Is not that clear, how exactly that would happen.

Also, who would discover new content?
Apperently, right now a lot of users already vote on the same face again and again, because there is already a bunch of votes on.
With n^2 this would increase, I guess.
Why 'waste' my vote on that nice poem, when I can get way more curator rewards back, by voting on that daily trending?

The actual payout would depend on where all the other r_shares were allocated to.

If the highest paying post had 2x as many r_shares as the second highest, the latter would get 1/4 of the rewards of the first one.

Why 'waste' my vote on that nice poem, when I can get way more curator rewards back, by voting on that daily trending?

Because with n^2 there is at least a chance that the majority of stakeholders will find a consensus of what 'good content' is and maybe one day they all agree that it is a nice poem and it will go viral and end up in trending.

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