Statistical analysis of tree diameter and age.

Statistical analysis of tree diameter and age.

Correlation between Diameter and Age: R (correlation coefficient) = 0.88820958 or 88.82%. Judging by R It would seem the Linear model may be appropriate.

The form of the line is Linear, with a positive direction, the line is moderately strong. The line also has no unusual features, no outliers, leverage, or influential points.

C.
D.
The Residuals show a slight curved pattern and also show a change in spread.
E. It would generally underestimate as they’re more positive residuals which means the model was underestimating.

A.
(1.8)^2=3.24 Ft. Sq.
(1.8)^2=3.24 Ft. Sq.
(2.2)^2=4.84 Ft. Sq.
(4.4)^2=19.36 Ft. Sq.
(6.6)^2=43.56 Ft. Sq.
(4.4)^2=19.36 Ft. Sq.
(7.7)^2=59.29 Ft. Sq.
(10.8)^2=116.64 Ft. Sq.
(7.7)^2=59.29 Ft. Sq.
(5.5)^2=30.25 Ft. Sq.
(9.9)^2=98.01 Ft. Sq.
(10.1)^2=102.01 Ft. Sq.
(12.1)^2=146.41 Ft. Sq.
(12.8)^2=163.84 Ft. Sq.
(10.3)^2=106.09 Ft. Sq.
(14.3)^2=204.49 Ft. Sq.
(13.2)^2=174.24 Ft. Sq.
(9.9)^2=98.01 Ft. Sq.
(13.2)^2=174.24 Ft. Sq.
(15.4)^2=237.16 Ft. Sq.
(17.6)^2=309.76 Ft. Sq.
(14.3)^2=204.49 Ft. Sq.
(15.4)^2=237.16 Ft. Sq.
(11)^2=121 Ft. Sq.
(15.4)^2=237.16 Ft. Sq.
(16.5)^2=272.25 Ft. Sq.
(16.5)^2=272.25 Ft. Sq.

The scatter plot looks exactly the same.
B.
C.
The residuals seem to be in no pattern and would indicate this model may be more appropriate to use.
D. (18)^2= 324 ft. Sq. 7.2396107 + 0.11301057(324)= 43.86 years old if 18 inch diameter was squared.
7.2396107 + 0.11301057(18)= 9.27 Years old if tree is 18 inches in diameter.