A solution to a problem about bulls, cows and calves

Hello again, 

If you are here you either didn’t solve the problem or solved it and just wanted to check whether I am full of shit. Well, I’ll give you the benefit of the doubt, judge for yourself.  

So the original equations were:

B+CW+CF = 100
10B+5CW+.5CF = 100  

Click here if you don't know what the problem  is 

Solution: We make an assumption based on the cost of each kind of animal that the solution will have less bulls than cows and less cows then calves. Then let’s start with 1 bull. The equations then becomes:

(1) CW + CF = 99 
(2) 5CW+ .5CF = 90 

Then

CW+CF = 99 10
CW+CF = 180

Subtracting

 9CW=81   Thus CW=9  Plugging back to (1)  9+CF=99  or CF = 90

Final solution:  Bull = 1, Cows = 9, Calves= 90

That's all folks.  If you didn't find this fun punish me by not up-voting.

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BTW, if you would like to check out my remote corner of Steemit Universe, here are the links to my original short stories:  

The Hole   
The Day Pill    
How I froze an annoying memory