On every 31 day month there are always 3 days of the week that appear 5 times in the month. So out of 7 weekdays 3 of them will have 5 days that month. Thus the answer is 3/7 (approx. 0.42857143...)
If that month starts with a Su, there will be 5, if it starts with a Sa, there will be 5, if it starts with a Fr, there will be 5 and with any other day there will be 4.
That is 3 days out of 7, the chance being 3/7 or about 42.8571429%
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On every 31 day month there are always 3 days of the week that appear 5 times in the month. So out of 7 weekdays 3 of them will have 5 days that month. Thus the answer is 3/7 (approx. 0.42857143...)
If that month starts with a Su, there will be 5, if it starts with a Sa, there will be 5, if it starts with a Fr, there will be 5 and with any other day there will be 4.
That is 3 days out of 7, the chance being 3/7 or about 42.8571429%
Nicely done. I was trying to think of some complex equation, not thinking to consider the first day of the month.
:)
great content!