Inverse Hyperbolic Trigonometry as Logarithms: coth^-1(x)

in DTube4 years ago (edited)


In this video I go over converting inverse hyperbolic trig functions to logarithms and prove that the function inverse hyperbolic cotangent or coth-1(x) is equal to 1/2·ln((x+1)/(x-1)).

Download the notes in my video: https://1drv.ms/b/s!As32ynv0LoaIiJN9LbtYuf6NN8zJ0A?e=fvWWuT

View video notes on the Hive blockchain: https://peakd.com/hive-128780/@mes/inverse-hyperbolic-trigonometry-as-logarithms-coth-1-x

Related Videos:

Inverse Hyperbolic Trigonometry as Logarithms: sech-1(x): http://youtu.be/cF0Pbdkae30
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Inverse Hyperbolic Trigonometry as Logarithms: sinh-1(x): http://youtu.be/AQT2uHlyjEs
Inverse Hyperbolic Trigonometry as Logarithms: tanh-1(x): http://youtu.be/vfOWS8Y_rQw
Inverse Hyperbolic Trigonometry as Logarithms: cosh-1(x): http://youtu.be/lsUcHzQAlHQ
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I don't always write functions as logs but when I do it's usually when dealing with inverse hyperbolic trig ;)

View video notes on the Hive blockchain: https://peakd.com/hive-128780/@mes/inverse-hyperbolic-trigonometry-as-logarithms-coth-1-x

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