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RE: Fifth contest let's solve these logical problems. by josegonzalito

in Zero to Infinity3 years ago

Problem one
The peasant originally had only 21 pesos.
This because, for the first cross, the amount in his pocket multiplied by two, that is, (21×2)=42. He gave 24 pesos to the devil for the deal (42-24)=18
For the second cross, the 18 pesos that was left in his pocket also multiplied by two (18×2)=36, he gave 24 pesos to the devil again, remaining 12 pesos on him.
For the third cross, the 12 pesos left in his pocket also multiplied by two (12×2)=24, but because of the deal, he gave all the 24 pesos to the devil. He finally had nothing left on him again.

Problem two
The inn owner served them a total of 27 potatoes.
The first who woke ate 1/3 of the 27, that is 9, leaving 18 of them for his/her friends.
The second who woke up also ate 1/3 of the remaining 18, that is 6, leaving 12 for his/her friends.
The third person who woke also ate 1/3 of the remaining 12 that is 4, leaving 8 for his/her friends.

In total, they ate 19 potatoes leaving 8

For them to have eaten equally, each person was supposed to eat 9 potatoes.

Thank you @josegonzalito for the contest, and I invite @zology69 and @fadil1 to participate in this contest

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