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RE: Fifth contest let's solve these logical problems. by josegonzalito
Q1. He had 21 pesos
Q2. 27 patatoes was served
1/3 of 27 = 9
9 was for each farmers
The first eat 9 potatoes
Remainder 27 - 9 =18
The second eat 1/3 of the remaining
1/3 of 18 =6
Remaining 18-6 =12
1/3 of the remainder from farmer 2
1/3 of 12 =4.
The suppose to eat 9 each so
Famer 1 will eat nothing =0
Farmer 2 eat 6 out of 9 (9-6)=3
Farmer 3 eats 4 out of 9 (9-4)=5
I invite @camzy ,@bright-obias