Fourth Contest let's solve these logical problems. by josegonzalito

in Zero to Infinity2 years ago

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Good evening friends, today we continue with the fourth edition of the contest let's solve these logical problems, because I would like to share with you my passion for all those riddles and problems that challenge us to see beyond what we see with the naked eye and we must apply lateral thinking and logical thinking to solve them.

I am very grateful and pleased with the receptivity that the contest has had since the number of participants increases with each opportunity.

In some problems we just have to apply the basic mathematical operations, in others, no specific knowledge is needed, just think a little differently. Attention to detail is often the key to finding the solution.

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Problem 1 Jumbled Equation.

Problemas Lógicos 4-02.png

Problem 2 The Sheep .


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With these 2 challenges we continue this series of contests.

I hope you enjoy the contest answering the challenges.

Participating is very easy, you just have to leave your answers in a comment on this publication.

Rules

  1. Leave your answers in a comment on this publication.
  2. Only one entry is allowed per person.
  3. You cannot edit your answer.
  4. The entire Steemit community can participate.
  5. Share this post on your wall. (ReSteem)
  6. In case there is more than one winner with the correct answers, the prize will be distributed among all the winners.

Please try to solve the problems yourself and do not get carried away by the results of the other participants. Be confident of your own results and share them.

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The prize to be distributed is 8 steems.

The contest will be available until Friday 28MAY at 12:00 pm (Venezuelan Legal Time).


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Thanks to the support of @tarpan and @zero-to-infinity

CC: @steemcurator01, @steemitblog

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My answers
Problem 1
(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2

There are 5 sheep and of them 1 is an ewe

Hi @josegonzalito, thanks for these puzzles I really like solving them. I have a question and a suggestion, if thats ok.

Question : Sheep have 2 hooves on each leg, but together its called a cloven hoof, so which one are you referring to in Problem 2. Should we count 1 hoof per leg or 2?

Suggestion : It would be good to give separate higher prize for the first person giving all correct answers and distributing the remaining prize among others. Otherwise others can blindly copy the answers and the person who put the effort solving it first will not get any benefit. I have the answers for Problem 1, but once I post it anyone can copy. :-)

Tienes toda la razón y lo tomaré en cuenta amigo.. así lo haré... Muchas gracias por tu participación y por tu sugerencia...

Thank you @josegonzalito, can you clarify about my question for Problem 2? Should we count 1 hoof per leg or 2 hooves?

Toma en cuenta solo 1 por pata...

Thank you, my answers

Problem 1
(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2
5 sheep of which 1 is ewe

Answers: (Problem 1)
(2x2) + 7 = 11
(3x3) + 5 = 14
(6x11) + 3 = 69


Answers: (Problem 2)
The total number of sheep is five,including one ewes.

Question #1
(2x2) + 7 = 11
(3x3) + 5 = 14
(6x11) + 3 = 69

Question #2
There are five sheeps, one amougst them is an ewes.

This is my entry @josegonzalito

Problem 1: (jumbled equations)
(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2: (The sheep)
Let, r= number of ram
e= number of ewe
Total number of sheep head= (e+r)
But each sheep has four(4) hooves
Therefore, total hooves= (4e+4r)
And the number of ewe tongues is e, because every sheep has one tongue
Expressing this mathematically,

4e(r+e)^2=100
Dividing both sides by 4
e(e+r)^2=25
But 25 is a perfect square of a prime number (5), but e and r are non-negative integers
Thus, e= 1 and r=4 and total number of sheep heads=5

Therefore, there are five (5) sheep, of which only one (1) is an ewe

Answer,
Problem 1
(2x3) + 5 = 11,
(3x4) + 2 = 14,
(5x13) + 4 = 69

Problem 2
5 sheep of which 1 is ewe

Answer

Problem

1)(2x3)+5=11
2)(3x4)+2=14
3)(6x11)+3=69

problem 2

There are a total of 5 sheeps of which only 1 is an ewe

Answers: (Problem 1)
(2x2) + 7 = 11
(3x3) + 5 = 14
(6x11) + 3 = 69


Answers: (Problem 2)
The total number of sheep is five,including one ewes.

Answer,
Problem:1
(2x3) + 5 = 11,
(3x4) + 2 = 14,
(5x13) + 4 = 69

Problem:2
5 sheep of which 1 is ewe

Question #1
(2x2) + 7 = 11
(3x3) + 5 = 14
(6x11) + 3 = 69

Question #2
Total number of sheep = five, one amongst them is an ewe.

Answer to the problem no. 1

(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69


Answer to the problem no. 2

Total 5 sheep including 1 ewe


Logic

{5*(5*4)*1}= 100


Thank you

@josegonzalito please kindly check the first jumbled equation , I think the letter are not correct or if we are going to move the mathematics sign only ...

Solution to problem 2 :we have only 25 sheep and 75 ewe

The numbers in the equation are correct. The signs must remain in place; you only have to change the position of the numbers, even individually each number. Thanks for your participation.

Alright thanks for the reply

Problem 1(Answer)
(2x2) + 7 = 11
(3x3) + 5 = 14
(6x11) + 3 = 69

Problem 2 (Answer)
Sheep is five,including one ewes.

Hola @josegonzalito, un pregunta? en el primer problema tu dices que los números cambia pero los signos quedan iguales? pero los números del resultado también se mueven?

Tengo esa duda.

Correcto, todos los números cambian de manera individual, incluso los del resultado... Saludos hermano...

Thank you @josegonzalito for this interesting puzzle my Answers are

Answer 1

  1. (5x4) + 1 = 21
  2. (31x1) + 3 = 34
  3. (6x9) + 2= 56

Answer 2

5 Sheep of which 1 is Ewe

My Answer-1

(5x4) + 1 = 21
(31x1) + 3 = 34
(6x9) + 2= 56

My Answer-2
Sheep= 5 and 1 of them is ewe

Answer 1

  1. (5×4)+1= 21
  2. (31×1)+3= 34
  3. (6×9)+2= 56

Answer2

There are 5 sheep and out of them 1 is ewe

Solution to proplem 1

(5x4) + 1 = 21
(31x1) + 3 = 34
(9x6) + 2 = 56

Solution to problem 2

5 Sheep of which 1 is Ewe

Problem 1 solution:

(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2 solution:

Total 5 Sheep of which 1 is ewe.

Question #1
(2x2) + 7 = 11
(3x3) + 5 = 14
(6x11) + 3 = 69

Question #2
There are five sheeps, one amougst them is an ewes.

Problem 1 Solution:

(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2 Solution:

There are 5 sheep and 1 of them is a ewe.

Question 1:

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Question 2:

The total number of sheep is five and one is an ewe.

Problem 1 Solution:
(2x3) + 5 = 11
(3x4) + 2 = 14
(5x13) + 4 = 69

Problem 2 Solution:
There are 5 sheep and of them 1 is ewe

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