# Fourth Contest let's solve these logical problems. by josegonzalito

Good evening friends, today we continue with the fourth edition of the contest ** let's solve these logical problems**, because I would like to share with you my passion for all those riddles and problems that challenge us to see beyond what we see with the naked eye and we must apply lateral thinking and logical thinking to solve them.

I am very grateful and pleased with the receptivity that the contest has had since the number of participants increases with each opportunity.

In some problems we just have to apply the basic mathematical operations, in others, no specific knowledge is needed, just think a little differently. Attention to detail is often the key to finding the solution.

Problem 1 Jumbled Equation.

Problem 2 The Sheep .

I hope you enjoy the contest answering the challenges.

Participating is very easy, you just have to leave your answers in a comment on this publication.

# Rules

- Leave your answers in a comment on this publication.
- Only one entry is allowed per person.
- You cannot edit your answer.
- The entire Steemit community can participate.
- Share this post on your wall. (ReSteem)
- In case there is more than one winner with the correct answers, the prize will be distributed among all the winners.

Please try to solve the problems yourself and do not get carried away by the results of the other participants. Be confident of your own results and share them.

# The prize to be distributed is 8 steems.

The contest will be available until Friday 28MAY at 12:00 pm (Venezuelan Legal Time).

Thanks to the support of @tarpan and @zero-to-infinity

kombatnatuka (54)2 years agoMy answers

Problem 1

(2x3) + 5 = 11

(3x4) + 2 = 14

(5x13) + 4 = 69

Problem 2

There are 5 sheep and of them 1 is an ewe

josegonzalito (65)member 2 years agoTwitter

mchandra (55)2 years agoHi @josegonzalito, thanks for these puzzles I really like solving them. I have a question and a suggestion, if thats ok.

Question : Sheep have 2 hooves on each leg, but together its called a cloven hoof, so which one are you referring to in Problem 2. Should we count 1 hoof per leg or 2?

Suggestion : It would be good to give separate higher prize for the first person giving all correct answers and distributing the remaining prize among others. Otherwise others can blindly copy the answers and the person who put the effort solving it first will not get any benefit. I have the answers for Problem 1, but once I post it anyone can copy. :-)

josegonzalito (65)member 2 years agoTienes toda la razón y lo tomaré en cuenta amigo.. así lo haré... Muchas gracias por tu participación y por tu sugerencia...

mchandra (55)2 years agoThank you @josegonzalito, can you clarify about my question for Problem 2? Should we count 1 hoof per leg or 2 hooves?

josegonzalito (65)member 2 years agoToma en cuenta solo 1 por pata...

mchandra (55)2 years agoThank you, my answers

Problem 1

(2x3) + 5 = 11

(3x4) + 2 = 14

(5x13) + 4 = 69

Problem 2

5 sheep of which 1 is ewe

shopon700 (68)2 years agoAnswers: (Problem 1)

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Answers: (Problem 2)

The total number of sheep is five,including one ewes.

abduljawad002 (60)2 years agoQuestion #1

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Question #2

There are five sheeps, one amougst them is an ewes.

padmore (55)2 years agoThis is my entry @josegonzalito

Problem 1: (jumbled equations)

(2x3) + 5 = 11

(3x4) + 2 = 14

(5x13) + 4 = 69

Problem 2: (The sheep)

Let, r= number of ram

e= number of ewe

Total number of sheep head= (e+r)

But each sheep has four(4) hooves

Therefore, total hooves= (4e+4r)

And the number of ewe tongues is e, because every sheep has one tongue

Expressing this mathematically,

4e(r+e)^2=100

Dividing both sides by 4

e(e+r)^2=25

But 25 is a perfect square of a prime number (5), but e and r are non-negative integers

Thus, e= 1 and r=4 and total number of sheep heads=5

Therefore, there are five (5) sheep, of which only one (1) is an ewe

nishatoishi (59)2 years agoAnswer,

Problem 1

(2x3) + 5 = 11,

(3x4) + 2 = 14,

(5x13) + 4 = 69

Problem 2

5 sheep of which 1 is ewe

awuduabangiba (55)2 years agoAnswer

## Problem

1)(2x3)+5=11

2)(3x4)+2=14

3)(6x11)+3=69

## problem 2

There are a total of 5 sheeps of which only 1 is an ewe

ayeshask (56)2 years agoAnswers: (Problem 1)

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Answers: (Problem 2)

The total number of sheep is five,including one ewes.

haideremtiaz (68)2 years agoAnswer,

Problem:1

(2x3) + 5 = 11,

(3x4) + 2 = 14,

(5x13) + 4 = 69

Problem:2

5 sheep of which 1 is ewe

verdad (57)2 years agoQuestion #1

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Question #2

Total number of sheep = five, one amongst them is an ewe.

engrsayful (75)2 years ago (edited)## Answer to the problem no. 1

(2x3) + 5 = 11

(3x4) + 2 = 14

(5x13) + 4 = 69

## Answer to the problem no. 2

Total 5 sheep including 1 ewe

## Logic

{5*(5*4)*1}= 100

Thank you

richgang (62)2 years ago@josegonzalito please kindly check the first jumbled equation , I think the letter are not correct or if we are going to move the mathematics sign only ...

Solution to problem 2 :we have only 25 sheep and 75 ewe

josegonzalito (65)member 2 years agoThe numbers in the equation are correct. The signs must remain in place; you only have to change the position of the numbers, even individually each number. Thanks for your participation.

richgang (62)2 years agoAlright thanks for the reply

meekey41 (48)2 years agoProblem 1(Answer)

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Problem 2 (Answer)

Sheep is five,including one ewes.

fuentesjo3006 (64)2 years agoHola @josegonzalito, un pregunta? en el primer problema tu dices que los números cambia pero los signos quedan iguales? pero los números del resultado también se mueven?

Tengo esa duda.

josegonzalito (65)member 2 years agoCorrecto, todos los números cambian de manera individual, incluso los del resultado... Saludos hermano...

ziabutt3836 (52)2 years agoThank you @josegonzalito for this interesting puzzle my Answers are

Answer 1

Answer 2

5 Sheep of which 1 is Ewe

adventurer21 (39)2 years agoMy Answer-1(5x4) + 1 = 21

(31x1) + 3 = 34

(6x9) + 2= 56

My Answer-2Sheep= 5and1of them iseweattiyaasghar (63)2 years agoAnswer 1Answer2There are 5 sheep and out of them 1 is ewe

emyprince (49)2 years agoSolution to proplem 1

(5x4) + 1 = 21

(31x1) + 3 = 34

(9x6) + 2 = 56

Solution to problem 2

5 Sheep of which 1 is Ewe

ftz (60)2 years ago (edited)Problem 1 solution:(2x3) + 5 = 11

(3x4) + 2 = 14

(5x13) + 4 = 69

Problem 2 solution:Total 5 Sheep of which 1 is ewe.

pocoloco01 (68)2 years agoQuestion #1

(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Question #2

There are five sheeps, one amougst them is an ewes.

onority (41)2 years ago## Problem 1 Solution:

(2x3) + 5 = 11(3x4) + 2 = 14(5x13) + 4 = 69## Problem 2 Solution:

There are 5 sheep and 1 of them is a ewe.chenty (68)2 years agoQuestion 1:(2x2) + 7 = 11

(3x3) + 5 = 14

(6x11) + 3 = 69

Question 2:The total number of sheep is five and one is an ewe.

mrm.bipul (25)2 years agoProblem 1 Solution:(2x3) + 5 = 11(3x4) + 2 = 14(5x13) + 4 = 69Problem 2 Solution:There are 5 sheep and of them 1 is ewe