Do you know how many labor and materials are needed to make sloof?
In accordance with the understanding of the work of simple building structures and tracing in the field work process so today I will discuss about the calculation of labor and material needs on the work of reinforced concrete sloof.
Sloof is a building structure that is on the foundation, because the position of sloof located on the ground floor then the existence of sloof rarely seen.
There are three types of sloof are often used, namely sloof of reinforced concrete, sloof of brick and sloof of wood.
Sloof serves as a bearer of the building load and passes the load to the foundation, as a column binder, as a wall load divider, wall load retention and as a barrier of ground reaction forces.
We try to plan a sloof with length of 8.00 m with a cross section of 0.15 m x 0.20 m.
Sloof is using plain concrete iron with the following specifications:
| Description | Information |
|---|---|
| Reinforcement | 4 Ø12 (Read 4 bar plates of plain concrete iron with a diameter of 12 mm) |
| Beugel / stirrup | Ø6 - 150 (Read Beugel diameter of 6 mm with a distance of 0.15 m) |
The technical drawings below can explain our description above.
In reinforced concrete work there are 3 aspects that we must count, that is
1 Concrete (we will use concrete type K - 225)
2 Spawning
3 Formwork
A. Concrete calculation (m3)
Is known.
| Description | Information |
|---|---|
| Length | 8.00 m |
| Width | 0.15 m |
| Height | 0.20 m |
Resolutions:
Length x width x height
8.00 x 0.15 x 0.20 = 0.24 m3
So the total volume of concrete is 0.24 m3
B. Calculation of enlargement (Kg)
Main Reinforcement :
Is known :
| Description | Information |
|---|---|
| Plain concrete iron coefficient | 0.00616225 * D93 ^ 2 |
| Iron reinforcement length | 8.10 (8.00 plus iron bending each end 5 cm) |
| The amount of reinforcement | 4 bars |
| Iron Diameter | Ø12 |
Answer:
| Description | Information |
|---|---|
| Iron coefficient x Diameter of iron | Kg / m |
| (0.00616225 * D93 ^ 2) x 12 | 0.887364 Kg / m |
| (Iron Length x Amount) x Kg / m | Kg |
| (8.10 x 4) x 0.887364 | 28.7505936 Kg (32.40 m) |
Beugel / brace :
Is known :
| Description | Information |
|---|---|
| Plain concrete iron coefficient | 0.00616225 * D93 ^ 2 |
| The length of the steel reinforcement | 0.56 m ((width of sloof - concrete blanket (0.06) + High sloof - concrete blanket (0,06)) x 2) |
| Iron count | 54 units (Sloof Length / Beugel Distance + 1) |
| Iron Diameter | Ø6 |
Answer:
| Description | Information |
|---|---|
| Iron coefficient x Diameter of iron | Kg / m |
| (0.00616225 * D93 ^ 2) x 6 | 0.221841 Kg / m |
| (Iron Length x Amount) x Kg / m | Kg |
| (0.56 x 54) x 0.221841 | 6.70847184 Kg (30.24 m) |
Then the total iron is (reinforcement iron+brace iron ) = Kg
28.7505936 + 6.70847184 = 35.45906544 Kg
C. Working formwork (m2)
In sloof work we only use the formwork on the left and right side only, the bottom side has been closed by the foundation of mountain rock so it does not need to be reckoned again.
Is known :
| Description | Information |
|---|---|
| Sloof Length | 8, 00 m |
| High Sloof | 0.22 (Co Co ctnsient 2 cm) |
| Side used | 2 sides |
| Used as many as | 4 times |
Answer:
(Length x height x side) / use formwork = m2
(8.00 x 0.22 x 2) / 4 = 0.88 m2
Total volume
| Description | Information |
|---|---|
| Concrete (K-225) | 0.24 m3 |
| Iron Concrete | 35,45906544 Kg (rounded 35.45 kg) |
| Formwork | 0.88 m2 |
I use coefficients according to Indonesian National Standard
Concrete Work (K-225)
To complete the work of 1 M3 of concrete type K-225 is required:
| Description | Information |
|---|---|
| Worker | 1,650 Person Per Day |
| Stonemason | 0.275 Person Per Day |
| Foreman | 0,028 Person Per Day |
| Overseer | 0.083 Person Per Day |
| Portland Cement | 371 Kg |
| Concrete Sand | 698 Kg |
| Gravel | 1047 Kg |
| Water | 215 Liter |
The solution is to make the multiplication between coefficient and volume required
| Description | Information | Amount |
|---|---|---|
| Worker | 1,650 Person Per Day x 0.24 m3 | 0.396 Person |
| Stonemason | 0.275 Person Per Day x 0.24 m3 | 0.066 Person |
| Foreman | 0,028 Person Per Day x 0,24 m3 | 0.00672 Person |
| Overseer | 0.083 Person Per Day x 0.24 m3 | 0.01992 Person |
| Portland Cement | 371 Kg x 0.24 m3 | 89.04 Kg |
| Concrete Sand | 698 Kg x 0.24 m3 | 167.52 Kg |
| Gravel | 1047 Kg x 0.24 m3 | 251.28 Kg |
| Water | 215 Liters x 0.24 m3 | 51.6 Liter |
Spawning Jobs
To complete the work of 1 kg of plain concrete iron is required:
| Description | Information |
|---|---|
| Worker | 0,0070 Person Per Day |
| Blacksmith | 0,0070 Person Per Day |
| Foreman | 0.0007 Person Per Day |
| Overseer | 0.0004 Person Per Day |
| Plain Concrete Iron | 1.050 Kg |
| Concrete Wire | 0.015 Kg |
The solution is to make the multiplication between coefficient and volume required
| Description | Information | Amount |
|---|---|---|
| Worker | 0,0070 Person Per Day x 35.45 kg | 0.24815 Person |
| Blacksmith | 0,0070 Person Per Day x 35.45 kg | 0.24815 Person |
| Foreman | 0.0007 Person Per Day x 35.45 kg | 0.024815 Person |
| Overseer | 0.0004 Person Per x 35.45 kg | 0.01418 |
| Plain Concrete Iron | 1.050 Kg x 35.45 kg | 37.2225 Kg |
| Concrete Wire | 0.015 Kg x 35.45 kg | 0.53175 Kg |
Works Formwork
To complete the 1M2 job Sloof formwork is required:
| Description | Information |
|---|---|
| Worker | 0,5200 Person Per Day |
| Carpenter | 0.2600 Person Per Day |
| Foreman | 0.0260 Person Per Day |
| Overseer | 0.02604 Person Per |
| Wood Klass III | 0.0450 M3 |
| Ordinary nail | 0.3000 Kg |
| Oil Formwork | 0,1000 Liter |
The solution is to make the multiplication between coefficient and volume required
| Description | Information | Amount |
|---|---|---|
| Worker | 0,5200 Person Per Day x 0.88 m2 | 0.4576 Person |
| Carpenter | 0.2600 Person Per Day x 0.88 m2 | 0.2288 Person |
| Foreman | 0.0260 Person Per Day x 0.88 m2 | 0.02288 Person |
| Overseer | 0.02604 Person Per x 0.88 m2 | 0.02288 Person |
| Wood Klass III | 0.0450 m3 x 0.88 m2 | 0.0396 m3 |
| Ordinary nail | 0.3000 Kg x 0.88 m2 | 0.0396 m3 |
| Oil Formwork | 0,1000 Liter x 0,88 m2 | 0.088 Liter |
To complete the work of reinforced concrete sloof with length of 8.00 m, height of 0.20 m and width of 0.15 m using the main reinforcement 4 bars Ø12 and beugel/brace Ø6 distance of 0.15 m require.
| Description | Amount |
|---|---|
| Worker | 1.101750 People |
| Stonemason / Carpenter / Blacksmith | 0.542950 People |
| Foreman | 0.054415 People |
| Overseer | 0.056980 People |
| Portland Cement | 89.04 Kg |
| Concrete Sand | 167.52 Kg |
| Gravel | 251.28 Kg |
| Water | 51.6 Liter |
| Plain Concrete Iron | 37.2225 Kg |
| Concrete Wire | 0.53175 Kg |
| Wood Klass III | 0.0396 m3 |
| Ordinary nail | 0.0396 m3 |
| Oil Formwork | 0.088 Liter |
Thus the technical calculation of the needs of workers and materials on the work of Sloof reinforced concrete Size 0.15 x 0.20 x 8.00 m.
After the analysis of this calculation is completed then we can estimate how and what is needed during the work period and hopefully this calculation analysis is useful for young engineers and those working in the field of construction.
This is all I can write on this occasion, for all the lack of writing and as a servant of God I apologize.
Thanks to friends who have visited this blog and have provided constructive comments.
source:
en.wikipedia.org Reinforced concrete
Do you love science? then join us at steemstem using @science tags and @steemstem, you can also chat with us at steemstem chat. channel.
Best regards @kharrazi
Hi @kharrazi, you fail to create the table in your post, please check it again, and fix it.
Nice post. Please visit my blog,
which table should I fix? thank you before.
This is my Android view from eSteem app there is error to show table.
but, from browser its look good.
You need to check it from your eSteem app android or ios. You need to saparate paragraph, better to create using html coding.
ok, it's time good-karma up date esteem application and i have not app esteem in my phone. it seems i should learn html coding with you :)