How to Sketch a Parabola - Example 3 (y = x^2 + 6x + 10)
Graphing the function y = x2 + 6x + 10, we go through the normal process of finding its concavity, y-intercept, and turning point / vertex but this particular example does not have any x-intercepts because as a positive parabola, the y-coordinates for the vertex and intercepts are positive, and therefore, the parabola will not cross the x-axis.
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