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RE: Intelligence Contest #8 - Win 100% of the SBD + Free Votes

in #contest7 years ago

There you go. Updated it.
My reasoning is that from the first two equations I get a relation between the distance to Curnorax and the distance to Smurnorax. C and S standing for the respective distances, I get: C=S/2-150.
Inserting that into my third equation I get:
A(S/2-150)=G(2xS-50) which yields the S of my previous post, which is too small.

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You made a little mistake... Why would you multiply the speed by the respective distances?

If you multiply speed by distance, you get... well... it's nothing measurable really.. You have to divide the distance by the speed to obtain the time it takes to reach certain places. From there you can easily derive the distances. So try dividing instead of multiplying.

I tried to solve it again and succesfully obtained the same answer as I had obtained the first time I tested it. Good Luck if you're still interested :P

Uhh, that was quite a stupid mistake. If I didn't make another one, I get that Thorinax reaches Smurnorax 1496.25 seconds after Glorfmorax has reached Curnorax.

If this is not correct I'm done. :-)

Yeah, that's correct :)

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