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RE: "SLC-S22W1/Variables and Expressions"

in #burnsteem252 years ago (edited)

Remaining part of task 3

Expression #2

Evaluate this expression: (x^2 + 2x - 3) / (x + 1) when x = 2

Step 1

In the first step, we substitute the value of x in the given expression, in nominators and in denominators

20241219_134942.jpg

Step 2

First, i solve the nominator, here exponential term is solved as 2^2 = 2×2 = 4 . Then to solve the multiplication as 2×2 =4 the above expression changes as

20241219_141949.jpg

Step 3

On performing addition and subtraction in nominators and denominators we proceed step by step

20241219_142151.jpg20241219_142243.jpg20241219_142341.jpg

final answer= 5/3 = 1.6

8DAuGnTQCLptHK3w4xbU3SMDsfFVWre2qvkWUixoMRzeeZXveHXMV1rvtM6iBgwZtNiSbAE7DRT5faN2o7NtomKHG37ookAvaJVKjhQiVEfnxtUzySsQqRLrhqxYkpotNDLRVeocsNX1vZr3i1aiJ8ZVhYsjo54JRYhwqMLLrbg.png

Expression #3

Solve the following equation: 2x + 5 = 3(x - 2) + 1

This expression is a bit different from others because here the equivalent sign devide the expression in two halves. So im going to solve these one by one and then equate them.

Step 1

20241219_143356.jpg

Step2

In this step i simply multiple 3 with the terms in parentheses to solve it
20241219_143428.jpg

Step 3

In the following step just addition is performed to get i.e -6 +1= -5

20241219_143702.jpg

step5

Because L.H.S is already in simplest form so both side can be equivalent as follow
L.H.S = R.H.S

20241219_143732.jpg
On rearranged this equation
we get
5+5 =3x -2x

Step5

Here is the final answer we got

20241220_195618.jpg

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5/3= 1.67

that "7" was clicking in my mind, but I just forgot to include it. Thanks for pointing it out. It will help me to be more focused

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