# 《西瓜居家电路课》#8 解刨电箱的详细数据

in esteem •  22 days ago

1：Ps=18kW Kx=1 Pjs=18kW cosφ=0.9 Ijs=30.1A_NM7-63 3P 63A
①Ps=18kW Kx：这个电箱的总耗电量为：18千瓦（kw）
②1 Pjs=18kW cosφ=0.9功率因数
③Ijs：Pe=180000W , 设备组容量，
④Ijs=30.1A计算负荷为30.1A
⑤NM7-63 3P 63A=空气开关3P型。回路第7.63A

2：YJV22-1KV 5×16.FC：
①YJV ：交联聚乙烯绝缘钢带铠装聚氯乙烯护套电力电缆（铜芯)
②22：代表垲装
③1KV 5×16：5条芯，每条芯：16㎡
④FC：PVC套管敷设

1：WL10:2P/25A
①wl：10=代表着回路第10
②2P/25AL△n箱内空气开光：两匹25安（A）

2：L△n0.03A/NB7LE-63/KM10
①L△n0.03A/=内置基础耗电0.03瓦（W）
②NB7LE-63/KM10=套管固定管材：Φ 63。10公里（km）

3:YJV-1KV 3×6 .PC32
①YJV=交联聚乙烯绝缘钢带铠装聚氯乙烯护套电力电缆（铜芯)
②1KV 3×6=3条芯，每条芯6㎡
③PC32=用Φ30PVC套管敷设
④L10_LED灯带_3KW=第10个回路使用LED灯带，总耗电量3000挖（W）

### 为与@cn-stem 一起推动科普。《西瓜居家电路课》互动有奖游戏，本期话题：LED灯带每米有多少瓦（W）

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