Chemistry Challenge # 4

in #steemstem7 years ago (edited)

Once more I ( @jaki01 ) let run my #chemistrychallenge under the SteemSTEM flag to support this still growing science community which in my eyes adds a lot of value to our Steemit community!

What could be more fun than activating your brain and at the same time having the opportunity to win up to 15 STEEM. :-)

Rules - what are the requirements to win the prize?


The winner is the first person to post the correct solution (correct number and correct unit; solution process required). The prize for the correct answer is 15 STEEM. We will send it to the winner immediately after the article is paid out (7 days after posting).

If nobody is able to determine the solution before Sunday, June 4th, 2017 at 10 pm (German time!) the prize (15 STEEM) will be added to the next competition (bringing that one up to 30 STEEM!).

SOURCE: pixabay

Your Chemistry Challenge to Solve:


Imagine a room with an open window contains a mass of exactly 51600 g air which has a density of ρ(air) = 1.29 kg/m3.
At the beginning temperature T = 0 °C and pressure p = 101 kPa.
Assume temperature gets increased now by 13 °C (pressure stays constant). That means the volume of the air is increasing as well.

Questions:

How many cubic meters (m3) air escape of the room (through the open window) and how much kilojoule (kJ) of volume work will be achieved during this process?

Some Things Ya Might Want To Know!

  • 1 Pa = 1 kg∙m-1∙s-2
  • 1 J = 1 kg∙m2∙s-2
  • 0 °C = 273.15 K (kelvin)
Sort:  

1.90 cubic metres of air escapes and -192 kilojoules of volume work is acheaved?!

Maybe, maybe not - you may convince us with your calculations though. :-)

The winner is the first person to post the correct solution (correct number and correct unit; solution process required).

Here is what I did :)
http://imgur.com/a/m0f7r

Looks great!
Congrats to the winner of this round! :)

Yaaay lovely..still got my chemistry during summer break!! :) thanks for the opportunity

Yes, very well done! I hope you enjoyed that quiz. :)

hi @steemstem can you help me starting in steem

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