Hi @rasel72, thank you for participating in the Industrial Electrical Homework. We have assessed your Homework post , and the below captures our assessments.

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A. You have been able to select the names of Transformers 2 by looking at their performance and ratings. The name of the transformer can be easily determined by looking at the turns of the primary and secondary coils of the transformer. I hope you understand the basic point.

You have calculated both voltage and turns ratio. I only asked to find the turns ratio in the homework because I wanted students to find the turns ratio from three ratios. There is no need to calculate the voltage ratio.

B. You have not mentioned some important parts of the transformer, like the radiator. Then, you couldn't match the name with the picture. While writing the working of the bushing of the transformer, you have not written the main words. Primary and secondary voltage supplies are provided through the bushing of the transformer, and step-up and step-down can be determined. I hope you understand your mistake.

C. The transformer given in your picture is a three-phase transformer, and its size seems to be used by many loads. Single-phase transformers are generally used on a small scale in rural areas.

D. The load will be equal if you use a 5556 KVA transformer for a 5000 KW load. So you need to use a transformer of 6000 KVA or 6 MVA rating. You can use the transformer at 80% load. I hope you understand.

E. You made a big mistake by looking at the nameplate to learn about transformers. You wrote 415 kV, which would be 415 volts. If it is 415 KV, it will be a step-up transformer. I hope you understand your mistake. If there is a mistake, such as an electrical one, a lot of damage will be done.

F. When you find the transformer's HT and LT current, the result matches the nameplate rating of the transformer mentioned above. Your calculations are correct.

G. Power Factor works to prevent wastage in the use of electricity. In the industrial sector, power factor values are kept standard with power capacitors.

H. You can say that the major difference between the two transformers is that one is used for high load and one for low load.

The efficiency of the transformer is higher than that of other electrical devices because there are no rotating parts inside it. I hope you understand your mistake.

Thank you for reading Industrial Electrical Lessons and participating in the homework. The lesson will be useful in your real life to gain knowledge as an industrial electrician. I work in industrial electrical so I know these things are very important. Hope you succeed. Good luck to you.